snow? Options

[schwab]

um...where the hell did this come from

Wed
Mar 22

PM Rain / Snow Showers
41°/30° 30%

(weather.com)

[Psykopath]

Welcome to Lubbock...?

[GOB]

awesome

[False Dude]

WE'RE ALL GONNA DIE!!!!

[kcroxyoursox]

yeah they said weds night so im guessing late (if at all)

[Mommy]

[woody]

i remember in 03 when it snowed in the begining of april

that sucked

[GOB]

when i was a sophomore in high school (in colorado), it snowed in the middle of july. crazy shit.

[Rocky]

i remember in 03 when it snowed in the begining of april

that sucked

That was the night i let a friend stun me with a stun gun. Memories.

[Mommy]

i remember in 03 when it snowed in the begining of april

that sucked

yes, yes it did suck. i hate the weather here

[GOB]

That was the night i let a friend stun me with a stun gun. Memories.

that is awesome.

[chook]

would be cool!

[zetec]

prepare for the first snow-cocks of the year

(this was 2005's first snow-cock, and no, I did not make it. I only hugged it.)

[jonathan83]

welcome to west texas

[woody]

This is from 2001 in the c-dubs courtyard

we were told to take it down so we chopped it into pieces and put in the free speech pavilion

[Slutter McGee]

It snowed Monday in Amarillo. It probably wont stick. be more like rain when it hits the ground.

[schwab]

it wont stick....wont be enough snow

[Spectatrix]

It snowed last night here in Albuquerque... wasn't even supposed to that I know of. I woke up 20 minutes ago, saw white through my curtains and was like... WTF???

[schwab]

hmmm there is a thin layer of snow outside my window...

[JRockTTU]

Damn Zetec, you sure do look like you feel at home hugging a giant cock.

[James]

It hasn't snowed at Tech yet. Must be only in parts of the town?

[schwab]

It hasn't snowed at Tech yet. Must be only in parts of the town?

i live across university from tech, there is just snow on top of the car ports mainly, but its nto much....

[Spectatrix]

It was all snowy when I went to class this morning.... then an hour later you couldn't tell that it had snowed at all. It was all gone.

We've had flurries here off and on throughout the day, though.

[basschick]

yea it was flurrying on me when I was running just now

[taatimmi]

snow now.

[Testm0nkey]

oh shit

[Testm0nkey]

its just started but its sticking to the ground thus far
doesnt feel really cold though

[Rocky]

Who will be the first person to get a pic with them sitting naked in the snow !

We don't have to see your goods, we just wanna know you got a frozen butthole !

[Spectatrix]

It's supposed to snow around 10 pm again here. Boo!

[schwab]

yeah for snow

[TetraGrammaton C...]

yeah, when i got out of my meeting there were random flurries, then as i drove home the snow became more substantial
it was neat

[DaveFireDancer19]

i want snow

but im in southern louisiana


booo

but i did get gumbo today!

[Testm0nkey]

im going to leave a soda in the front yard and it better fucking be cold by the time i get back!

[Throwdown]

it just started snowing, right when i was putting on my sweats to go run

go figure

[Mommy]

I fucking hate this weather. fucking gay

[schwab]

I fucking hate this weather. fucking gay

exact same thing my roommate said 5 min ago

[DaveFireDancer19]

I fucking hate this weather. fucking gay

move to houston..that way you'll just expect rain, 100% humidity, and temps of..i dunno atleast 50 at all times


with a week of winter in december

[Psykopath]

Ah,so NOW it's winter...

[James]

I fucking hate this weather. fucking gay

What don't you hate?

[Throwdown]

and now it stopped.

thank you so much for snowing just long enough to ruin my chance to go running tonight. die god, die

[Mommy]

What don't you hate?

the list is short.

[moebary]

What don't you hate?

waffles

[Mommy]

waffles

precisely. that, french fries, my bf, Stephanie, and my mom.

[Throwdown]

precisely. that, french fries, my bf, Stephanie, and my mom.

AND HANK

[Mommy]

AND HANK

I love Hank most of all

[Rocky]

HEY YOU CUNT

[Mommy]

HEY YOU CUNT

hmm my list is getting too long. I dont sound as hateful anymore.


I FORGOT ROCKY. ROCKY WILL ALWAYS HAVE A SPECIAL PLACE IN MY .....





butt sex

[Dogmeat]

PUSSY!

[Testm0nkey]

yup after rtidingaround on my bi9ke i can say yes its cold poutsiode

frozen

[Rocky]

was your soda cold ?

[Testm0nkey]

i had forgotten to put one in the yard

i failed at being a scientist

[James]

F!

You should've taken my algebra class since you like getting F's so much!

[Testm0nkey]

yeah dude. when you teach it again ill take it

but only then1!

[Billy]

Hey, since we're on the topic of algebra, how do you solve something like y^3 - 6y^2 - y + 6 = 0 by hand? I have completely forgotten how to do a third order+ polynomial without a calculator.

[James]

You'd solve that one by factoring by grouping. Notice that the first two have a common factor of y^2 and the latter two have a common factor of -1, so you can factor it as (y^2-1)(y-6) but then you have difference of two squares, so you have (y+1)(y-1)(y-6)

Alternatively, you could use Descartes' Rule of Signs along with the Rational Zero Theorem.

Lastly, you could try using a numerical method by hand, but that would just be a pain and might as well use a calculator.

[James]

yeah dude. when you teach it again ill take it

but only then1!

I may or may not teach a math class this summer. Dunno if they'll let me even though I told them I changing majors. If I do, it'd be Math 1300 - Contemporary Math. Will be interesting to learn what contemporary math is.

[Rocky]

I am contemporary man

[Jyan]

It's snowing again.

[Throwdown]

It's snowing again.

not in my hood

[Psykopath]

It's snowing again.

yep, it is over here as well (near marketstreet)

[Testm0nkey]

snow here in south overton

[James]

No snow on northwest loop.

[schwab]

not near university...but then again you posted a long ass time ago

[woody]

shitty

[Jwilly]

the snow will end once i use head and shoulders!!!

[Billy]

You'd solve that one by factoring by grouping.  Notice that the first two have a common factor of y^2 and the latter two have a common factor of -1, so you can factor it as (y^2-1)(y-6) but then you have difference of two squares, so you have (y+1)(y-1)(y-6)

Alternatively, you could use Descartes' Rule of Signs along with the Rational Zero Theorem.

Lastly, you could try using a numerical method by hand, but that would just be a pain and might as well use a calculator.

Thank you james =)

And can you do one more just so I can fully understand what you're saying:



(Just replace the dashes with a power. I'm sure you remember diffeq)

[kcroxyoursox]

its snowing on campus right now
you cant really see it because its pretty light
but maybe if it keeps up long enough...

[schwab]

its snowing on campus right now
you cant really see it because its pretty light
but maybe if it keeps up long enough...

yeah when i was walking home i noticed that

[James]

Thank you james =)

And can you do one more just so I can fully understand what you're saying:



(Just replace the dashes with a power. I'm sure you remember diffeq)

Alright. This one will be a bit longer since it involves a lot more work than factoring by grouping.

Consider the polynomial function: f(x)=x^3 - 7y^2 + 7y + 15

First, apply Descartes' Rule of Signs to determine the number of possible positive and negative zeros. Descartes' Rule of Signs states that the number of sign changes in f(x) indicates the maximum number of positive sign changes, including decrements of 2n (i.e. if there are 5 sign changes, then there are 5, 3, or 1 positive roots. if there there are 4 sign changes, then there are 4, 2, or 0 positive roots. Furthermore, it states that the number of sign changes in f(-x) indicates the maximum number of negative sign changes, including decrements of 2n.

The number of sign changes in f(x) is 2 (there's one from x^3 to -7y^2 and then one more from -7y^2 to 7y), so there are 2 or 0 positive roots.

f(-x)=-x^3 - 7y^2 - 7y + 15

The number of sign changes in f(-x) is 1 (there's one from -7y to 15), so there is exactly 1 negative root (This is NICE!)

Now apply the Rational Zero Theorem. It states that every polynomial, written generally as f(x)=a_n x^n + a_n-1 x^n-1 + ... + a_1 x^1 + a_0 has potential rational zeros at the ratio of the factors of a_0 over a_n. For instance, if a_0 had factors of 1, 2, -1, and -2 and a_n had factors of 1, 3, -1, and -3, then all possible rational zeros would be: 1/1, 1/3, 1/-1, 1/-3, 2/1, 2/3, 2/-1, 2/-3.

In our problem, a_0 is 15, so its factors are 1, 3, 5, 15, -1, -3, -5, and -15. Additionally, a_n is 1, so its factors are 1 and -1

Thus, all possible rational zeros are the following: 1, 3, 5, 15, -1, -3, -5, -15

Now, recall from earlier that we know we have exactly one negative root. If we're lucky enough for this to be a doctored problem, then that root will be rational, so let's try the negative numbers first. You should be able to tell by just looking at it that -15 and -5 will cause it to blow up too much, so don't bother trying those first. Let's try f(-1). If you get f(-1)=0, then you found a root. f(-1)=-1 - 7 - 7 + 15 = 0. Therefore, -1 is a root. That means x+1 is a factor of our polynomial.

Now, you can do one of two things. You can do polynomial division, which always works in reducing your polynomial by one degree, or you can try your other possible rational zeros. I prefer polynomial division as it's not that difficult.

Evaluate (x^3 - 7x^2 + 7x + 15) / (x+1) and you'll get (x^2 - 8x + 15) which you know factors to (x-5)(x-3).

Therefore, the factors of this polynomial are (x+1)(x-5)(x-3).

[schwab]

what the fuck deos this have to do with snow

[James]

Billy asked.

[Billy]

Wow James. Thanks a bunch.

[James]

No problem.